C++ Program to enter an integer and output it in the reversed form
Program to enter an integer and output it in the reversed form
#include <iostream.h>
#include <conio.h>
void main()
{
clrscr();
long int num1,num2,rnum=0;
cout << "Enter an integer : " << endl;
cin>>num1;
num2=num1;
do
{
rnum=rnum*10;
int digit=num1%10;
rnum+=digit;
num1/=10;
}
while(num1);
cout << "The integer you typed is " << num2 << "." << endl;
cout << "The reversed integer is " << rnum << "." << endl;
getch();
}
This program takes in an integer num1 as a screen input from the user.
It then outputs the integer in its reversed form using the 'cout' command.
OUTPUT
The integer you typed is 987.
The reversed integer is 789.
#include <iostream.h>
#include <conio.h>
void main()
{
clrscr();
long int num1,num2,rnum=0;
cout << "Enter an integer : " << endl;
cin>>num1;
num2=num1;
do
{
rnum=rnum*10;
int digit=num1%10;
rnum+=digit;
num1/=10;
}
while(num1);
cout << "The integer you typed is " << num2 << "." << endl;
cout << "The reversed integer is " << rnum << "." << endl;
getch();
}
This program takes in an integer num1 as a screen input from the user.
It then outputs the integer in its reversed form using the 'cout' command.
OUTPUT
The integer you typed is 987.
The reversed integer is 789.